Question

if 2 and -3 are the zeros of the polynomial x*2+(a+1)x+b,then find the value of a and b​

Answer 1

Answer:

a=0

a=0b=-6

Step-by-step explanation:

Sum of roots is =-1 = -(a+1)

Therefore a=0

product of roots = -6 =b

Therefore

b = -6

Answer 2

Step-by-step explanation:

sum of zeros= 2+(-3)= -1

-b/a= -1

-(a+1)/1 = -1

-(a+1)= -1

a+1=1

a=0

product of zeros= 2*-3= -6

c/a= -6

b/1 = -6

b= -6

The equation is x^2+x -6