if 2 and -3 are the zeros of the polynomial x*3 + ax*2 +bx - 12 , find the values of a and b
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Solution
Given :-
- Polynomial , x³ + ax² + bx -12 = 0
- 2 & -3 are roots this Equation
Find :-
- Value of a & b
Explanation
We know,
Here, 2 & -3 are roots this Equation that's means these are satisfied sm quadratic equations.
Case 1.
- When, x = 2
==> 2³ + a (2)² + 2b - 12 = 0
==> 8 + 4a + 2b - 12 = 0
==> 4a + 2b = 12 - 8
==> 2(2a + b) = 4
==> 2a + b = 4/2
==> 2a + b = 2 __________(1)
Case 2.
- when, x = -3
==> (-3)³ + a(-3)² + b(-3) - 12 = 0
==> -27 + 9a - 3b = 12
==> 3(3a - b) = 12 + 27
==> 3a - b = 39/3
==> 3a - b = 13_________(2)
add equ(1) & equ(2)
==> 5a = 15
==> a = 15/5
==> a = 5
Keep in equ(2)
==> 3×5 - b = 13
==> b = -13 + 15
==> b = 2
Hence
- Value of a be = 5
- Value of b = 2
_________________
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