Question

if 2 and -3 are the zeros of the quadratic polynomial x squared +( a + 1) x + b then find the values of a​

Answer 1

zeros of p(x) are
x= 2 & -3
p(x) = x^2 + (a +1) x + b
putting p(2)

p(2) = (2)^2 + (a+1) (2) + b
0 = 4+ 2a + 2 +b
0 = 6 + 2a +b
-6 = 2a + b (1)
putting p(-3)
p(-3) = (-3)^2 + (a+1)(-3) + b
0 = 9 -3a-3 + b
0= 6 -3a + b
3a - b = 6 (2)
(1) +(2)
2a + b = -6
+ 3a - b = 6
= 6a = 0
a = 0/6
a = 0 here is ur answer bacha