Question

if 2 and -3 are the zeros of the quadratic polynomial x² +(a+1)X+b , then find the value of a and b​

Answer 1

Let one zero of the polynomial be alpha and another zero be beta.

Then,

2=Alpha

-3=Beta

Sum of zeroes =-(a+1)

=> 2+(-3) = -a-1

=> -1=-a-1

=> a=-1+1=0.

Product of zeroes=b÷1

=> 2(-3) =b

=> -6=b.

Answer 2

Answer:

a = 0 , b = -6

Step-by-step explanation:

your answer is in the attachment