Question

If -2 and 3 are the zeros of the quadratic polynomial x2+(a+1)x+b then find a and b. (Ans. -2,-6)

Answer 1

Answer:

Step-by-step explanation:

p(x)=x^2+(a+1)x+b

p(-2)=(-2)^2+(a+1)(-2)+b=0

4-2a-2+b=0

b-2a=-2--(1)

p(3)=(3)^2+(a+1)3+b=0

9+3a+3+b=0

3a+b=-12--(2)

solve (1) and (2)

-5a=10

a=-2

put a value in(1)

b+4=-2

b=-6