Question

If -2 and 3 are the zeros of the quadratic polynomial x²+(a+1)x+b then​

Answer 1

Answer:

substitute -2 and -3 separately for x and the substract the answer u obtained for -2 and-3 and u will get the value of a and b

Answer 2

Answer:

x²-x-6=0

a=-2;b=-6

Step-by-step explanation:

since -2,3 are zeroes of the polynomial, if we substitute these values at x the polynomial becomes zero

x² +(a+1)x+b

x=-2

(-2)² +(a+1)(-2) +b =0⇒ 4-2a-2+b=0

2a-b=2⇒eq.1

x=3

3² +(a+1)3+b=0⇒9+3a+3+b=0

3a+b=-12⇒eq.2

eq.1+eq2⇒5a=-10

a=-2

Substituting,

2(-2)-b=2⇒b=-6

a=-2;b=-6

The equation is,

x²-x-6=0