If -2 and 3 are the zeros of the quadratic polynomial x2 + (a +1)x + b then
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x2+ax+x+b
(-2)2+a(-2)+(-2)+b
4-2a-2+b
2-2a+b=0 (1st eq)
-2a+b+2=0
(3)2+a(3)+(3)+b
9+3a+3+b
12+3a+b=0
3a+b+12 (2nd eq)
2nd eq-1st eq
3a+b+12=0
-2a+b+2=0
(+) (-) (-)
5a+10=0
5a=-10
a=-2
I hope this answer may help you
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