Question

if -2 and 3 are thr zeroes of the quadratic polynomial x^2+(a+1)x+b then find a and b​

Answer 1

Step-by-step explanation:

Answer :-

since -2 and 3 are the zeros of the quadratic polynomial then we can write as

(x+2)(x-3) = x²+(a+1)x+b

x²-x-6 = x²+(a+1)x+b

now on comparing me get

a+1=-1

a=-2

b=-6