Question

If –2 and 3 are two zeroes of the polynomial x4 +ax2 + bx + a, find a and b.
Plz answer​

Answer 1

Answer:

hey

Step-by-step explanation:

given that,2 and 3 are the zeroes of x³+x²+bx-30.

p(x)=x³+ax²+b(2) -30

NOW,

p(2)=(2)³+a(2)²+b(2)-30

=8a+4a+2b-30

=4a+2b-22

=2a+b-11

2a+b=11...(1)

AND,

p(3)=(3)³+a(3)²+b(3)-30

=27+9a+3b-30

=9a + 3b-3

=3a+b-1

3a + b =1 ...(2)

SINCE 2and 3 are zeroes of given polynomial.

SO,SUBSTRACTING (1)and(2)

2a+b=11

3a+b=11

-a=10

a= -10

substituting a=-10 in (1)

2(-10) +b=11

-20+b=11

b=11+20

b=31

therefore,the value of a and b are-10 and 31 respectively

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Answer 2

Step-by-step explanation:

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