If 2 and 3 are zeroes of the polynomial 3x2-2kx+2m, find the value of k and m
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Answered by
123
given , 3x²- 2kx + 2m with zeroes 2 and 3
here a= 3,b=2k ,c=2m
sum of zeroes = 2+3 = 5 product of zeroes = 2×3= 6
⇒5= -b/a ⇒6 = c/a
⇒5= -2k/3 ⇒ 6 =2m/3
3×5= -2k 6×3 = 2m
15/-2 = k 18/2=m
∴k= -15/2 ∴ m = 9
here a= 3,b=2k ,c=2m
sum of zeroes = 2+3 = 5 product of zeroes = 2×3= 6
⇒5= -b/a ⇒6 = c/a
⇒5= -2k/3 ⇒ 6 =2m/3
3×5= -2k 6×3 = 2m
15/-2 = k 18/2=m
∴k= -15/2 ∴ m = 9
Answered by
24
Answer:
here a=3,b=2k,c=2m
sum of Zeroes =2+3=5
product of Zeroes =2×3=6
5=-b/a;6=c/a
5=-2k/3;6=2m/3
k =15/-2;m =18/2
:k=-15/2;m=9
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