Question

if -2 and 3 are zeroes of the polynomials X2 +(a+1) x+bthen find value of a and b​

Answer 1

Since -2 is a zero of the polynomial x^2 + (a+1)x + b, so x = -2 vanishes this polynomial i.e., it becomes zero.

Thus, (-2)^2 + (a+1)(-2) + b = 0

=> 4 -2a -2 + b =0

=> -2a + b + 2 = 0

=> 2a - b = 2

=> b = 2a - 2

Also, at the value of x = 3, the polynomial becomes zero.

=> (3)^2 + (a + 1)(3) + b = 0

=> 9 + 3a + 3 + b = 0

=> 3a + b = -12

=> 3a + 2a - 2 = -12

=> 5a = -10

=> a = -2

Thus, b = 2(-2) - 2 = -6

Answer 2

Step-by-step explanation:

if -2 and 3 are zeroes

then, the equation is x² - (-2+3)x + (-2).3 = 0

→ x²-x-6 = 0

so, by comparing with the equation, we get

1. (a+1) = -1.
2. b = -6.

so, the value of a = (-2)

and. b = (-6)

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