Question

if-2 and 3 are zeroes of the quadratic polynomials x square+ (p +1 ) x+q then find the values of p and q​

Answer 1

Answer:

p = 0 and q = -6

Step-by-step explanation:

We are given that -2 and 3 are zeroes of x² + (p + 1)x + q

We know that :

Sum of zeroes = -b ÷ a. and Product of zeroes = c ÷ a

Hence

p + 1 = -2 + 3. q = -2 × 3

p + 1 = 1 q = -6

p = 0

Hope this helps....

Answer 2

Answer:

p = -2   and  q = - 6

Step-by-step explanation:

If -2 and 3 are the zeroes of the given polynomial(and be 0), these must satisfy the equation for x = -2 and x = 3.

 For x = - 2 :  f(-2) = 0

⇒ (-2)² +  (p + 1)(-2) + q = 0

⇒ 4 - 2p - 2 + q = 0

⇒ 2p - 2 = q            

For x = 3 :   f(3) = 0

⇒ (3)² + (p + 1)(3) + q = 0

⇒ 9 + 3p + 3 + q = 0

⇒ 12 + 3p + (2p - 2) = 0

⇒ p = - 2

  thus. 2(-2) - 2 = q = - 6