if 2 and -3 are zeros of polynomial x3+ax2+bx-12 find the values of a and b
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x=2
6 + 4a + 2b - 12 = 0
2a + b = 3
x=-3
-9 - 6a - 3b - 12 = 0
2a +b = -7
therefore no solution exist for a and b
6 + 4a + 2b - 12 = 0
2a + b = 3
x=-3
-9 - 6a - 3b - 12 = 0
2a +b = -7
therefore no solution exist for a and b
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