Question

if 2 and -3 are zeros of the quadratic polynomial x2 + ( a + 1 ) x + b then find the values of a and b

Answer 1

let f(x)=x²+(a+1)x+b

since 2 and -3 are zeros of the quadratic polynomial

f(2)=0 and f(-3)=0

4+2a+2+b=0 and 9-3a-3+b=0


2a+b=-6 and 3a-b=6


by solving both of them

a=0 and b=-6

.I Hope this will help u ;)

Answer 2

2 and -3 are roots of the given equation.

So sum of the roots = 2 - 3 = -1 = - a - 1
- 1 = - a - 1
a = 0

Now their product = 2 x (-3) = -6
- 6 = b/1 = -6

There's your answer - a = 0 and b = -6!