Question

if 2 and -4 are zeros of the polynomial f(x)=x^2+ax-8, then find the value of a

Answer 1

Step-by-step explanation:

Refer to the above attachment.

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Answer 2

Answer:

The value of a = 2

Step-by-step explanation:

Given,

2 and -4 are zeros of the polynomial x²+ax-8

To find,

The value of 'a'

Recall the concept,

Ifα and β are the roots of the polynomial ax²+bx+c, then we have

Sum of roots =α + β = $\frac{-b}{a}$

Product of roots = αβ = $\frac{c}{a}$

Solution:

Comparing the given equation x²+ax-8 with ax²+bx+c we get

a = 1, b= a and c = -8

Since it is given that 2 and -4 are the roots of the polynomial x²+ax-8, we have sum of roots  = 2+(-4)  = $\frac{-a}{1}$

-2 = -a

a = 2

Answer:

The value of a = 2

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