Question

if 2 and -4 r zeroes of the polynomial f(x)=x^2 +ax-8, then the value of a?

pls give the correct answer pls!!!​

Answer 1

Answer:

As 2 and -4 are the zeroes of the given equation

Therefore,

If we put these values in the given equation it will be equal to zero.

Therefore,

(2)²+(2)a-8=0. or. (-4)²p+(-4)a-8=0

4+2a-8=0. or. 16-4a-8=0

2a=4. or. -4a=-8

a=2. or. a=2

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