Question

if 2 and alpha are zeros of 2x²-6x+2, then the value of alpha is. (a) 2. (b) 3. (c) 1. (d) 3​

Answer 1

Answer:

1

Step-by-step explanation:

we know that,

if ax^2+bx+c=0

Then Sum of roots = -b/a

here a=2,b=-6

So -b/a turns out to be -(-6/2) which is 3

we already have '2' as one of its roots, so to find the other root

Sum of roots = 2+(alpha)=3

The other root (alpha) turns out to be 1

Answer 2

Given,

Quadratic equation, $\[ = 2{x^2} - 6x + 2\]$

Zeros, $\[2,\alpha \]$

Solution,

Consider $\[a{x^2} + bx + c\]$ is a quadratic polynomial having two zeros.

Sum of zero $\[ = - \frac{b}{a}\]$

Observe the given equation,

$\[2 + \alpha = - \frac{{\left( { - 6} \right)}}{2}\]$

$\[ \Rightarrow 2 + \alpha = 3\]$

$\[ \Rightarrow \alpha = 1\]$

Hence the value of $\[\alpha \]$ is 1.

The correct option is (c), i.e. 1