if 2 and minus 3 of the zeros of the quadratic polynomial X square + (a +1) x + B then find the values of a and b
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put x=2 and x=-3 in eq.
4 +(a+1)2 +b =9-(a+1)3 + b
4+2a + 2 +b =9-3a -3 +b
6 +2a=6 -3a
5a=0
a=0
Now
x^2 +(0+1)x+b
put x=2
4 +2+b=0
b=-6
4 +(a+1)2 +b =9-(a+1)3 + b
4+2a + 2 +b =9-3a -3 +b
6 +2a=6 -3a
5a=0
a=0
Now
x^2 +(0+1)x+b
put x=2
4 +2+b=0
b=-6
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