Question

If 2^b^a – 2^a^b = 2^115 {2^2^c – 2^10}, where a, b and c are
odd prime numbers less than 10, then find the value of a^b/a^c.

plz answer quickly and any problem comment it... ​

Answer 1

Answer:first multiply the 2^115 with[ 2^2^c-2^10] then equate

after equating a^b=125 then the only possibility is 5^3.....so a=5 and b=3

then by putting the values of a and b you will get the value of c i.e 7

a^b/a^c=a^b-c=5^3-7=1/5^4=1/625

Answer 2

Answer:

Explanation:

Answer:first multiply the 2^115 with[ 2^2^c-2^10] then equate

after equating a^b=125 then the only possibility is 5^3.....so a=5 and b=3

then by putting the values of a and b you will get the value of c i.e 7

a^b/a^c=a^b-c=5^3-7=1/5^4=1/625