Question

if 2 black kings and 2 red aces are removed from a deck of 52 cards find the probability of getting (i)an ace of heart (ii)a king (iii)an ace (IV)a red card​

Answer 1

AnswEr :

When we'll remove 2 black kings & 2 red aces from a deck of 52 cards :

$:\implies\sf 52 - 4 \\\\:\implies\sf\bold\red{48}$

To find any probability formula is :

$\bf{\dag}\quad\large\boxed{\sf P(E) = \dfrac{Number\: of\: all\: outcomes}{Total \; number\; of \:outcomes}}$

Now, finding probability of getting 'an ace of Heart' :

• 1 red ace is already removed from cards. So,

$:\implies\sf \dfrac{0}{48} \\\\:\implies\sf 0$

$\star$ Probability of getting an ace of heart is 0.

$\rule{200}2$

Now, finding probability of getting a king:

• 2 Black kings are already removed from cards remaining cards are 2.

$:\implies\sf \cancel\dfrac{2}{48}$

$:\implies\sf \dfrac{1}{24}$

$\star$ Probability of getting a king is 1/24.

$\rule{200}2$

Now, finding probability of getting an ace:

$:\implies\sf \cancel\dfrac{2}{48}$

$:\implies\sf \dfrac{1}{24}$

$\star$ Probability of getting an ace is 1/24.

$\rule{200}2$

Now, finding probability of getting a red card :

$:\implies\sf \cancel\dfrac{24}{48} \\\\:\implies\sf\dfrac{1}{2}$

$\star$ Probability of getting a red card is 1/2.

Answer 2

Step-by-step explanation:

Aloha !

$[/texttt] { This is Twilight Astro}$

Total number of cards present in cards are "52"

If 2 black kings and 2 red aces are removed them "48" cards are remained.

Probability of getting an ace of heart:-

= 0/48

= 0

Probability of getting a king:-

= 2/48

= 1/26

Probability of getting an ace:-

= 2/48

=1/26

Probability of getting a red card:-

= 24/48

= 1/2

Hope you can understand

✌️