If 2 bulbs whose resistance are in the ratio 1:2. are connected in series what is the power dissapiated
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and is 1:2
as we know power=VI(v=voltage•I=current)
R=VI
so power=resistance
so 1:2
as we know power=VI(v=voltage•I=current)
R=VI
so power=resistance
so 1:2
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