Question

if 2 chords ab and ac of a circle with a centre at o are such that the centre o lies on the bisector angle bac , then prove that ab = bc .chords are equal​

Answer 1

Answer:

Step-by-step explanation:

If two chords AB and AC of a circle with centre O are such that the centre O lies on the bisector of angle BAC

=> ∠BAO  = ∠CAO = (1/2)∠BAC

Now join OB & OC

compare Δ OAB & OAC

OB = OC   ( Radius)

OA = OA  ( common side)

∠BAO  = ∠CAO

=>  Δ OAB ≅ OAC

=> AB = AC

QED

Proved.

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