Question

if 2 cos O = 3 then 2 cos O sin O/ 2 coso+sin o.....​

Answer 1

f(x)=sinx+

3

cosx

sinx+

3

cosx=03csos x =sin

2×3(1−sin 2 x)=sin 2 x.

3−4sin 2

x=0

sinx= 43 = 23

x= 3π , 34π

cosx=1− 43 = 41 = 21x= 3

π or π4π

tanx= cosx sinx = 3

x= 3π , 34π

∵2[cosx]+[sinx]=−3

⇒−1<cosx<1 & −1<sinx<1

fn[sinx]=−1,xϵ(π,2π)[∵[sinx]ϵ−1,0,1]

fn[2cosx]=−1,xϵ( 43π , 45π )[∵2cosxϵ[−2,2]2[cosx]ϵ−2,−1,0,1,2]

∴f(x) ranges from

3 and 3

HOPE IT HELPS YOU DEAR

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