If 2 cos theta-11costheta +5=0 then the permissible value of cos theta is
d) 1
a) 5
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Answer:
cosθ = 1/2
Step-by-step explanation:
Correct Question :-
If 2cos^2θ − 11cosθ + 5 = 0 then find possible values of cosθ.
Given,
To Find :-
Value of 'cosθ'.
Solution :-
We can write "-11cosθ" as : -10cosθ - cosθ
→ 2cos^2θ - 10cosθ - cosθ + 5 = 0
Taking '2cosθ' common :-
2cosθ(cosθ - 5) - 1 ( cosθ - 5) = 0
Taking 'cosθ - 5' common :-
(cosθ - 5)(2cosθ - 1) = 0
Equating both terms to zero :
cosθ - 5 = 0 , 2cosθ - 1 = 0
cosθ = 5 , 2cosθ = 1
cosθ ≠ 5 , cosθ = 1/2
∴ cosθ ≠ 5 because - 1 ≤ cosθ ≤ 1
→ cosθ = 1/2
Know More :-
1) - 1 ≤ sinθ ≤ 1
2) - 1 ≤ cosθ ≤ 1
3) secθ ≤ -1 and secθ ≥ 1
4) cscθ ≤ -1 and cscθ ≥ 1
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