if 2 cos theta=x+1/x prove that 2 cos 3theta=x^3+1/x^3
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Answer:
Step-by-step explanation:
Formula:
a3+b3=(a+b)3−3ab(a+b)
Given that,
2cosθ=x+x1
⟹cosθ=21(x+x1)
2cos3θ=2(4cos3θ−3cosθ)=8cos3θ−6 cosθ
=8.81(x+x1)3−6.21(x+x1)
=(x+x1)3−3(x+x1)
=(x+x1)3−3.x.x1(x+x1)
=x3+x31
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