If 2 cos (x + y) = 1, and 2 sin (x - y) = 1, find the
values of x and y.
Answers
Step-by-step explanation:
2 cos (x + y) = 1, and 2 sin (x - y) = 1
2 ( cosxcosy-sinxsiny) = 1
2 ( sinxcosy-cosxsiny) = 1
Apply this formula and solve
★ Solution :- ★
Given , that
• 2cos(x + y) = 1
Simplifying
➵ cos(x + y) = 1/2
As we know that cos60° = 1/2 . By comparing with cos(x + y)
➵ x + y = 60°
Assuming as equation 1
__________________________
And given that
• 2sin(x - y) = 1
Simplifying
➠ sin(x - y) = 1/2
As we know that sin30° = 1/2 . By comparing we th sin(x - y)
➠ x - y = 30°
Assuming as equation 2
__________________________
Now , equation (1 + 2)
➸ x + y + (x - y) = 60° + 30°
➸ x + y + x - y = 90°
➸ 2x = 90°
➸ x = 90° ÷ 2
➸ x = 45°
__________________________
Now, finding y by substituting the value of x in equation 1
➻ x + y = 60°
➻ 45° + y = 60°
➻ y = 60° - 45°
➻ y = 15°
_____________________________
Hence ,
- x = 45°
- y = 15°