Question

If 2 cot A = 3, find the value of:
5 sin A - 2 cos A/ 6 cos A + sin A



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Answer 1

Step-by-step explanation:

2 cot A = 3

cot A = 3/2

therefore ,by Pythagoras theorem

3^2+2^2 = hypotenuse^2

hyp = √ 13

now , sin A= 2/√13 and cosA= 3/√13 5×2/3-2×3/√3 /6×3/√13+2/√13

4/√13 ÷20/√13

=4/20

=1/5