If 2 dice are rolled simultaneously then the probability of getting a doublet of even numbers is
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Total no. of favourable outcome=(1,1), (2,2), (3,3),(4,4),(5,5), (6,6)=6
Total no.of possible outcome =6×6=36
P (of getting doublet)=6/36=1/6
Total no.of possible outcome =6×6=36
P (of getting doublet)=6/36=1/6
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