Question

IF 2 DICE ARE THROWN ,THEN PROBABILITY OF EVENT OF SUM OF NUMBERS ON UPPER FACE IS A MULTIPLE OF 7 IS

Answer 1

Answer:

lif 2 dice are thrown then total number of chances=12(1,2,3,4,5,6,7,8,9,10,11,12)

number of chances to get 7multiples=6{(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)}

p(7multiples)=6/12=1/2

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Answer 2

Answer:

n(s) = 36

n(A) = 6

P(A) = n(A) /n(S)

= 6/36

P(A) = 1/6

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