If 2 dice thrown simultaneously the probability of an even number on one end and multi0ul of 3 on other is
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favorable events
{2,3}{2,6}
{3,2}{3,4}{3,6}
{4,3}{4,6}
{6,2}{6,4}{6,6}
So total = 10
total number of outcome = 6*6 = 36
Probability = (10/36) = (5/18) = 0.27
{2,3}{2,6}
{3,2}{3,4}{3,6}
{4,3}{4,6}
{6,2}{6,4}{6,6}
So total = 10
total number of outcome = 6*6 = 36
Probability = (10/36) = (5/18) = 0.27
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