If 2 fair dice are rolled what is the probability of the sum being at least 10
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Answer:1/6
Step-by-step explanation:
n(s)=36
n(A)=6
P(A)=1/6
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Total possible outcomes=6^2=36
Total favourable outcomes=(5,5) (6,4) (4,6)=3
probability of (sum of being at least 10)=3/36=1/12
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