Question

If 2 + i is a zero of the polynomial x^3 - 5x^2 + 9x - 5, the
real zero is???​

Answer 1

SOLUTION = A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...

A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...By Hit and Trial,

A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...By Hit and Trial,---> f(3) = 0; which implies ( x - 3 ) is a factor of given polynomial...

A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...By Hit and Trial,---> f(3) = 0; which implies ( x - 3 ) is a factor of given polynomial...Hence, dividing by ( x - 3 ), we obtain the quadratic polynomial as:->

A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...By Hit and Trial,---> f(3) = 0; which implies ( x - 3 ) is a factor of given polynomial...Hence, dividing by ( x - 3 ), we obtain the quadratic polynomial as:->-----> x^2 + 8 x + 15;

A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...By Hit and Trial,---> f(3) = 0; which implies ( x - 3 ) is a factor of given polynomial...Hence, dividing by ( x - 3 ), we obtain the quadratic polynomial as:->-----> x^2 + 8 x + 15;===> ( x + 3 ) ( x + 5 );

A common approach would be to factorize but let's say, we avoid that for the cubic polynomial...By Hit and Trial,---> f(3) = 0; which implies ( x - 3 ) is a factor of given polynomial...Hence, dividing by ( x - 3 ), we obtain the quadratic polynomial as:->-----> x^2 + 8 x + 15;===> ( x + 3 ) ( x + 5 );Hence, By factor theorem, we obtain the zeroes as +3, -3 and -5.....

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