Question

if 2 is a root of Ax2+ kx+2a=0 then the other root​ don't scam guys​

Answer 1

Step-by-step explanation:

f(x)=ax

2

+bx+c=0,α<−2,β>2,a>0

∴f(0)<0

f(0)=0+0+c<0

∴c<0

D>0

∴b

2

−4ac>0

f(2)<0

4a+2b+c<0

∴4a+2∣b∣+c<0

f(−2)<0

∴4a−2b+c<0