Question

if 2 is a root of kx2+2x-1=0 then value of k​

Answer 1

Given 2 is a root

Keep x=2 as it is a root

then equation becomes

=>4k+4-1=0

=>k= -3/4

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Answer 2

Solution :

• we have to find the value of k

2 is a root of kx² + 2x - 1 = 0,

• So, x = 2

putting value of x in Given equation

⇒k(2)² + 2 × 2 - 1 = 0

⇒k(4) + 4 - 1 = 0

⇒4k + 3 = 0

⇒4k = -3

⇒k = -3/4

Hence

• value of k is -3/4

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