Question

If 2 is a root of QE 3x²+qx-8=0 and the QE 4x²-2qx+k=0 has equal roots, find the value of k.
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Answer 1

Answer:

q= -2

sub in 2nd eq

then use b^2-4ac=0

Answer 2

Answer:

k=32

Step-by-step explanation:

other root =4

2×4 =k/4

k=32