if-2 is a root of the equation 3x + 7x+p=0, find
the value of k so that the roots of the equation
x²+k(4x+k- 1) +p=0 are equal.
Answers
Answer:
There is a mistake in your question and it should be : If-2 is a root of the equation 3x² + 7x+p=0, find the value of k so that the roots of the equation x²+k(4x+k- 1) +p=0 are equal
Solution :
Given x = -2 is the root of equation 3x² + 7x + p = 0
Therefore, x = -2 satisfies the given equation.
3(-2)² + 7(-2) + p = 0
3(4) -14 + p = 0
12 - 14 + p = 0
-2 + p = 0
p = 2
So by putting the value of p in the given equation, we get
3x² + 7x + p = 0
3x² + 7x + 2 = 0
Now x² + k(4x + k - 1) + p = 0
Expanding the bracket, we get
x² + 4kx + k² - k + p = 0
Let's put up the value of p
x² + 4kx + k² - k + 2 = 0
The roots are equal.
Therefore, D = 0
b² - 4ac = 0
Comparing the equation with standard equation ax² + bx + c = 0, we get
a = 1, b = 4k and c = k² - k + 2
b² - 4ac = 0
(4k)² - 4 (1)(k² - k + 2) = 0
16k² - 4k² + 4k - 8 = 0
12k² + 4k - 8 = 0
4(3k² + k - 2) = 0
3k² + k - 2 = 0
3k² + 3k - 2k - 2 = 0
3k(k + 1) -2(k + 1) = 0
(3k - 2)(k + 1) = 0
3k - 2 = 0 ⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀k + 1 = 0
3k = 2 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ k = -1
k = 2/3 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀k = -1
The values of k are 2/3 and -1
Answer:
The above answer is correct