Question

If 2 is a root of the equation ax²−bx+2=0, then find the relation between a and b.

Plsss Help

Answer 1

Answer:

Given equation x

2

+bx+12=0

one root is 2

So, put x=2

4+2b+12=0

2b=−16

b=−8

Now roots of equation x

2

+bx+q=0 are equal

So, D=0

b

2

−4q=0

(−8)

2

−4q=0

4q=64⇒q=16

Answer 2

Given :- 2 is a root of equation ax²–bx+2 = 0.

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To Find :- a and b.

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Solution :-

• Here, x = 2.

putting value of x in the equation.

a×(2)²–b×2+2 = 0

4a–2b+2 = 0

2(2a-b+1) =0

2a-b+1 = 0.

2a-b = –1.

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