Question

If -2 is a root of the equation x^2+px-6=0 and the equation x^2-px+q=0 has equal roots,find the value of p and q

Answer 1

P(x)=x2+px-6 =0
Putting the value of x as -2
P(-2)=(-2)2+(-2)p-6 =0
P(-2)=4-2p-6=0
P(-2)= -2-2p=0
P(-2)= -2p=2
P(-2)= p=-2/2
p=-1
We got the value of p

Now putting the value of p in the equation to find the zeroes of it.
4x2-2(-1)x-6=0
4x2+2x-6=0
4x2+6x-4x-6=0
2x(2x+3)-2(2x+3)=0
(2x+3) , (2x-2)
(x=-3/2) ,(x=2/2 =1) ARE THE TWO zeroes
We have given that the second equation has the same factors as the first one therefore we will substitute the value of x as 1 and p as -1 .
G(x) =x2-px+q=0
G(1)=(1)2-(-1)(1)+q=0
G(1)=1+1+q=0
=2+q=0
q=-2
Therefore , p=-1 & q=-2

Answer 2

Answer:

This is the sum

Hope it helps you