Math, asked by Nayaz3290, 10 months ago

If 2 is a root of the equation x² + ax + 12 = 0 and the quadratic equation x² + ax + q = 0 has equal roots, then q
A. 12
B. 8
C. 20
D. 16

Answers

Answered by parthiv2002
2

Answer:

64=4q

q is 16

pls help me pls mark brainliest

Attachments:
Answered by nikitasingh79
3

Given :  2 is the root of x² + ax + 12 = 0 ………..(1)

and  the quadratic equation x² + ax + q = 0 has equal roots………(2)

solution :

Since, x = 2  is a root of equation (1) so it will satisfy the equation.

On putting x = 2  in equation (1)

x² + ax + 12 = 0  

(2)² + 2a + 12 = 0

4 + 2a + 12 = 0

16 + 2a = 0

2a = - 16

a = -16/2  

a = - 8

On putting a = - 8  in equation (2)

x² + ax + q = 0

x² + (- 8)x + q = 0

x² - 8x + q = 0

On comparing the given equation with ax² + bx + c = 0  

Here, a = 1 , b = - 8 , c =  q

D(discriminant) = b² – 4ac

D = (- 8)² - 4(1)(q)

D = 64 - 4q

D = 0 ( Equal  roots given)

64 - 4q = 0

64 = 4q

q = 64/4  

q = 16

Hence the value of q is 16 .

Option (d) is correct : 16

HOPE THIS ANSWER WILL HELP YOU……

 

Some more questions :  

If 2 is a root of the equation x² + bx + 12 = 0 and the equation x² + bx + q = 0 has equal roots, then q =

(a)8

(b)−8

(c)16

(d)−16

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If p and q are the roots of the equation x² − px + q = 0, then

(a)p = 1, q = −2

(b)b = 0, q = 1

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