Question

. If 2 is a root of the equation, x2+kx-16=0 thwn value of k is

Answer 1

Answer : The value of q = 16

Solution :

Given, 2 is a root of the equation x² + kx + 12 = 0,

Then Substituting x = 2 should make the equation hold good.

So,

⇒ x² + kx + 12 = 0

⇒(2)² + k(2) + 12 = 0

⇒ 4 + 2k + 12 = 0

⇒2k + 16 = 0

⇒2k = - 16

⇒k = - 16/2

⇒k = - 8

Also, Equation x²+kx+q=0 has equal roots, So discriminant should be 0

⇒Δ = 0

⇒b² - 4ac = 0

⇒ k² - 4(1)(q)= 0

⇒(-8)² - 4q = 0

⇒ 64 - 4q = 0

⇒ 64 = 4q

⇒64/4 = q

⇒ q = 16

Therefore, Value of q = 16

Answer 2

Answer:

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