Question

If 2 is a root of the equation x2 +px +12 = 0 , find the value of p

Answer 1

Answer:

if 2 is a root of the equation,

then put 2 in the equation.

2×2 + p×2 +12 =0

4+2p+12 = 0

2p+16 = 0

2p = -16

p = -16/2 = -8

Answer 2

Ans = 8

Step-by-step explanation:

Given,

x-2 is a root

ie, x=2

therefore 2(2) + p(2) + 12 = 0

4 + 2p + 12 = 0

2p + 16 = 0

p = 8