If -2 is a root of the equation x2+px-5=0, find the value of p and the value of other root.
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Answer:
p=-1/2 an roots are 2 and 5/2
Step-by-step explanation:
SINCE,-2 IS A ROOT OF P(X)
PUT X=-2 IN GIVEN EQUATION
=>(-2)^2+P(-2)-5=0
=>4-2P-5=0
=>-2P-1=0
=>-2P=1
=>P= -1/2
NOW PUT P IN GIVEN EQUATION
=>X^2-1/2X-5=0
( I simplified the equation and directly write it :p)
=>2X^2-X-5=0
BY FACTORIZATION
=>2X^2+4X-5X-10=0
=>2X(X+2)-5(X+2)=0
=>(X+2)(2X-5)=0
EITHER (X+2)=0. OR (2X-5)=0
=>X=-2. =>X= 5/2
THEREFORE VALUE OF P IS -1/2 AND ROOTS OF THIS EQUATION ARE -2 AND 5/2
IT IS MY FIRST TIME I HAVE WRITTEN A SOLUTION SO KINDLY PLZZ IGNORE THE SILLY MISTAKES
THANK YOU
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