If 2 is a root of the equation xsq.+6bx+12=0 and the equation has equal root find the value of b.
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the equation is x^2+6bx+12=0
and the root is 2
so put value of x=2 and solve
2^2+6*b*2+12=0
4+12b+12=0
and here comes b=-4/3
and the root is 2
so put value of x=2 and solve
2^2+6*b*2+12=0
4+12b+12=0
and here comes b=-4/3
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