If 2 is a root of the equation xsquare + kx +12 =0 and equation xsquare +kx +q =0 has equal roots find the value of q
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Answered by
7
Answer:
16
Step-by-step explanation:
x^2 + kx + 12 = 0
x = 2
2^2 + k*2 + 12 = 0
4 + 2k + 12 = =
k = -8
x^2 - 8x + q = 0
it has equal roots so
ax^2 + bx + c = 0 then b^2 - 4ac = 0 for equal roots
(-8)^2 = 4*1*q
64 = 4q
q = 16
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1
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