If 2 is a root of the equations ay2 + ay + 3 = 0 and y2 + y + b = 0, then find the
value of ab.
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Answer:
ay
2
+ay+3=0
as 1 is root then
⇒a(1)
2
+a(1)+3=0
⇒a+a=−3
⇒2a=−3
⇒a=−
2
3
y
2
+y+b=0
⇒(1)
2
+1+b=0
⇒2+b=0
⇒b=−2
∴ab=−
2
3
×−2=3
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