Question

if 2 is a root of the quadratic equation 3 X ^2+ px - 8 =0 and the quadratic equation 4x^2-2pX + K =0
has real and equal roots find k​

Answer 1

Answer:

Given: x=2 So putting the value of x=2 in eq. 3x2+px-8=0 3(2)2+2p-8=0 12+2p-8=0 4+2p=0 2(2+p)=0 2+p=0 P=-2 Now putting p=-2 in eq. 4x2-2px+k=0 D=0 (as it has equal root) (2p)2-4(4)(k)=0 (2×2)2-16k=0 16-16k=0 16 (1-k)=0 1-k=0 K=1

Answer 2

Step-by-step explanation:

when root is x= 2 = 3(2)^2+p(2)-8=0

12+2p-8=0

2p+4=0

p= -2

and 2nd eq.

4x^2-2px+k=0

16+8+k=0

k = 24