Question

if √2 is a salution of kx² + √12x -4 = 0 then
find the value of k​

Answer 1

Answer:

p(√2) = k(√2) + √12(√2) - 4

0= 2k + 2√6 -4

4= 2k+2√6

k = 4-2√6 /2

k= 4/2 -2√6/2

k= 2 - √6