If 2 is a zero of both the polynomial 3x²+ax-14 and 2x³+bx²+x-2, then value of a-2b is
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4
=2
3x²+ax-14
putting value of x that is 2 we get the value of a because being zero it give 0 after solving.
3×(2)²+a×2-14=0
3×4+2a-14=0
12-14=-2a
-2=-2a
1=a
now putting value of x in second equation,
2x³+bx²+x-2=0
2×(2)³+b×(2)²+2-2=0
2×8+4b=0
16+4b=0
4b=-16
b=-4
putting value of a & b in third equation,
2a+3b
=2×1+3×(-4)
=2-12
=-10
Answered by
6
Answer :
Since 2 is a zero of both the polynomial
Put x = 2 in both polynomial and equate to 0
3x²+ax-14
3*4 + 2a -14 = 0
2a = 2
a = 1
2x³+bx²+x-2
2*8 + 4b = 0
4b = -16
b= -4
a-2b = 1 - 2*-4 = 9
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