if -2 is a zero of f(x)=x^3+13x^2+32+20 , find its other zeroes
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Given,
f(x) = x^3 + 13x^2 + 32x +20
if, -2 is a zero then (x+2) is a solution of it. Let, f(x)=0
So,
x^3 + 13x^2 + 32x +20 = 0
or, x^3 + 2x^2 + 11x^2 +22x + 10x + 20 = 0
or, x^2(x+2) +11x(x+2) + 10(x+2) = 0
or, (x+2) ( x^2+11x+10) = 0
Then,
x = -2
and,
x^2+11x+10 = 0
or, x^2 +10x+x+10 = 0
or, x(x+10) + 1(x+10) = 0
or, (x+10) (x+1) = 0
so,
x = -10 and x = -1
Answer: x=-2, -10,-1
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