Question

If (-2) is a zero of kx3-2x-9, then find the value of k.​

Answer 1

Answer:

$p(x) = k {x}^{3} - 2x - 9 \\ p( - 2) = k( - {2}^{3} ) - 2( - 2) - 9 = 0 \\ - 8k - 5 = 0 \\ - 8k = 5 \\ k = \frac{ - 5}{8}$